FizzBuzz task in Swift

Task:
Write a program that prints the numbers from 1 to 100. But for multiples of three print "Fizz" instead of the number and for the multiples of five print "Buzz". For numbers which are multiples of both three and five print "FizzBuzz".

Solutions

Zero case - wrong solution (for better understanding)
In this case you never see "FizzBuzz" in output console, because all items that can be divided by 3 and 5 would be already count with print "Fizz".

// zero - wrong solution
for var i in 1..<101 {
    if i % 3 == 0 {
        print("Fizz")
    } else if i % 5 == 0 {
        print("Buzz")
    } else if i % 3 == 0 && i % 5 == 0 {
        print("FizzBuzz")
    } else {
        print(i)
    }
}

First - simple and easy

// first - for loop
for var i in 1..<101 {
    if i % 3 == 0 && i % 5 == 0 {
        print("FizzBuzz")
    } else if i % 3 == 0 {
        print("Fizz")
    } else if i % 5 == 0 {
        print("Buzz")
    } else {
        print(i)
    }
}

Second - using magic number 15 because 3 * 5 = 15

//second - foor loop and magic number 15 = 5 * 3
for var i in 1..<101 {
    if (i % 15 == 0) {
        print("FizzBuzz")
    } else if i % 3 == 0 {
        print("Fizz")
    } else if i % 5 == 0 {
        print("Buzz")
    } else {
        print(i)
    }
}

Third - using case instead of if..else statements

// third - for loop and case operator instead of switch
for var i in 1..<101 {
    switch i {
    case _ where i % 15 == 0:
        print("FizzBuzz")
    case _ where i % 3 == 0:
        print("Fizz")
    case _ where i % 5 == 0:
        print("Buzz")
    default:
        print(i)
    }
}

Fourth - make result string

//fourth - make a result string
for var i in 1..<101 {
    var str = ""
    if i % 3 == 0 {
        str = str + "Fizz"
    }
    if i % 5 == 0 {
        str = str + "Buzz"
    }
    if str == "" {
        str = String(i)
    }
    print(str)
}